Home Physics Newton's Laws of Motion Equilibrium of Forces Three blocks are arranged as shown in which …
Physics Newton's Laws of Motion Equilibrium of Forces MCQ (Single Correct)

Three blocks are arranged as shown in which ABCD is a horizontal plane. Strings are massless and both pulley stands vertical while the strings connecting blocks m 1 and m 2 are also vertical and are perpendicular to faces AB and BC which are mutually perpendicular to each other. If m 1 and m 2 are 3 kg and 4 kg respectively. Coefficient of friction between the block m 3 = 10 kg and surface is µ = 0.6 then, frictional force on m 3 is –

A
30 N
B
40 N
C
50 N
D
60 N

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Text Solution

Verified by Experts
The correct answer is:
C

Net force on m 3 = = 50 N

and limiting friction on m 3 = µm 3 g = 60N

System remain in equilibrium and friction on m 3 = 50 N

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